The time complexity of finding the Lowest Common Ancestor (LCA) in a Binary Search Tree (BST) using the algorithm described above is O(h), where h is the height of the tree.
In a balanced BST, the height of the tree is approximately log(n), where n is the number of nodes in the tree. This makes the time complexity of finding the LCA in a balanced BST O(log n).
However, in the worst-case scenario, when the BST is skewed (i.e., when all nodes are either left children or right children), the height of the tree becomes equal to the number of nodes in the tree (n). In this case, the time complexity of finding the LCA becomes O(n).
Therefore, the time complexity of finding the LCA in a BST using this algorithm ranges from O(log n) in the best-case scenario (balanced tree) to O(n) in the worst-case scenario (skewed tree).