Question

The coordination number of Ni in [Ni(C₂O₄)₃]^4- is

(A) 3

(B) 6

(C) 4

(D) 5

Answer 1

(B) 6

Co-ordination number of Ni in [Ni(C₂O₂)]⁴⁻ is 6.

Because \(C_2 O^{-3}_4\) is bidentate ligand and these ligands are 3 in number. 

So 2 x 3 = 6 be the co-ordination number.