Given HCF (2520, 6600) = 40, LCM (2520, 6600) = 252 × k, then the value of k is:

Question

Given HCF (2520, 6600) = 40, LCM (2520, 6600) = 252 \(\times \) k, then the value of k is:

(A) 1650

(B) 1600

(C) 165

(D) 1625

Answer 1

Correct option is (A) 1650

We know that,

HCF \(\times \) LCM = Product of two numbers

\(40 \times 252 \times k = 2520 \times 6600\)

\(k = \frac{2520 \times 6600}{252 \times 40}\)

\(\therefore k = 1650\)