If the rate equation for a reaction is dx/dt = k[H]^(1/2)[B]^(1/2) the order of reaction is

Question

If the rate equation for a reaction is \(\frac {dx}{dt} = k [H]^{1/2}[B]^{1/2}\) the order of reaction is

(A) 2

(B) 1/2

(C) 3/2

(D) 1

Answer 1

(D) 1

The rate equation for a reaction is \(\frac {dx}{dt} = k [H]^{1/2}[B]^{1/2}\) Order of the reaction with respect to H and B is 1/2 and 1/2 respectively.

Hence, the overall order of the reaction is \(\frac {1}{2}+\frac {1}{2} =1\).