π/3 - sin^{-1}(-1/2) =

Question

\(\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)=\)

(A) 0

(B) \(\frac{2 \pi}{3}\)

(C) \(\frac{\pi}{2}\)

(D) \(\pi\)

Answer 1

Correct option is (C) \(\frac{\pi}{2}\)

\(\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\)

\(= \frac \pi 3 - (- \frac \pi 6)\)

\(= \frac \pi 3 + \frac \pi 6\)

\(= \frac {3\pi} 6\)

\(=\frac{\pi}{2}\)