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in Mathematics by (38.5k points)

If \(a = \frac {1}{2!}+ \frac {^2C_2}{3!} + \frac {^3C_2}{4!} + \frac {^4C_2}{5!} + ...\)

\(b = 1 + \frac {^1C_0 + ^1C _1}{1!} + \frac {^2C_0 + ^{+2}C_1 + ^2C_2}{2!} + ...\)

Then \(\frac {2b}{a^2}\) equals to

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