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+1 vote
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in Physics by (50.1k points)

Find dimension of \(\sqrt {G. \mu}\), where G is universal gravitational constant and µ is energy gradient.

(1) [LT–2]

(2) [L2T–2]

(3) [LT3]

(4) [LT–1]

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1 Answer

+2 votes
by (50.3k points)

Correct option is (2) [L2T–2]

Dimension of \(\sqrt {G. \mu } = \sqrt{M^1L^3 T^{-2} \frac{M^1L^2T^{-2}}{L^1}}\)

\(= \sqrt{M^0L^4 T^{-4}}\)

\(= [L^2T^{-2}]\)

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