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यदि घटनाएँ A और B स्वतंत्र हों तो

(A) \(P(A \cap B)=P(A) P(B)\)

(B) \(P(A \cup B)=P(A)+P(B)-P(A \cap B)\)

(C) \(P(A \cup B)=0\)

(D) \(P(A \cap B)=P(A)+P(B)\)

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सही विकल्प है (A) \(P(A \cap B)=P(A) P(B)\) 

यदि घटनाएँ A और B स्वतंत्र हों तो \(P(A \cap B)=P(A) P(B)\)

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