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During Kinetic study of reaction 2A + B → C + D, the following results were obtained :

A[M] B[M] initial rate of formation of D
I 0.1 0.1 \(6.0 \times 10^{-3}\)
II 0.3 0.2 \(72 \times 10^{-2}\)
III 0.3 0.4 \(2.88 \times 10^{-1}\)
IV 0.4 0.1 \(2.40 \times 10^{-2}\)

Based on above data, overall order of the reaction is ……

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Best answer

Correct answer is : 3

\( \mathrm{r}=\mathrm{K}[\mathrm{A}]^{\mathrm{x}}[\mathrm{B}]^{\mathrm{y}} \)

\((\mathrm{I}) \,6 \times 10^{-3}=\mathrm{K}[0.1]^{\mathrm{x}}[0.1]^{\mathrm{y}} \)

\((\mathrm{IV}) \,2.4 \times 10^{-2}=\mathrm{K}[0.4]^{\mathrm{x}}[0.1]^{\mathrm{y}}\)

\((\mathrm{IV}) /(\mathrm{I})\)

\(4=(4)^{\mathrm{x}} \)

\(\mathrm{x}=1\)

\(\mathrm{r}=\mathrm{K}[\mathrm{A}]^{\mathrm{x}}[\mathrm{B}]^{\mathrm{y}}\)

\(\text {(III) } 2.88 \times 10^{-1}=\mathrm{K}[0.3]^{\mathrm{x}}[0.4]^{\mathrm{y}}\)

\(\text {(II) } 7.2 \times 10^{-2}=\mathrm{K}[0.3]^{\mathrm{x}}[0.2]^{\mathrm{y}}\)

\((III)/(II)\)

\(4=2^y\)

\( y=2\)

Overall order = x + y = 1 + 2 = 3

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Hope this helps

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