Answer: (a)n=3,I=2,m=1,s=+1/2
(a) n = 3 , l = 0 means 3s− orbital and n + 1 = 3
(b) n = 3 , l = 1 means 3p − orbital n + 1 = 4
(c) n = 3 , l = 2 means 3 d − orbital n + 1 = 5
(d) n = 4 , l = 0 means 4s − orbital n + 1 = 4
Increasing order of energy among these orbitals is
3 s < 3 p < 4 s < 3 d
∴ 3d has highest energy.
