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in JEE by (15 points)
 Equation of a straight line passing through point of intersection of \( L_{1}: 3 x-4 y+6=0 \) and \( L_{2}: x+y+2=0 \) which is situated at maximum distance from point \( (0,2) \) will be : (a) \( x-y+2=0 \) (b) \( x+y+2=0 \) (c) \( 2 x+y+4=0 \) (d) \( 2 x-y+4=0 \)

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1 Answer

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by (15.8k points)

761812077, hello

The correct answer is: (b) x + y + 2 = 0

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