Correct option is : (2) 2 : 9
Power Consumed \(= P = \frac{V^2}{R}\)
\(\frac{P_A}{p_B}=\frac{R_B}{R_A}\)
\(R_A = 2R_B\)
For Series Combination
\(P_S = \frac{V^2}{3R_B}\)
For Parallel Combination
\(P_P = \frac{3V^2}{2R_B}\)
\(\frac{P_S}{P_P} = \frac{2}{9}\)