If i is the current passing in the outer coil of radius R, then magnetic field at its centre.

B = \(\frac{\mu_0}{4\pi} \frac{2\pi i}{R}\)
∴ Magnetic flux through coil P
Φ = BA = \(\frac{\mu_0}{4\pi} .\frac{2\pi i}{R}(\pi r^2)\)
= \(\frac{\mu_0}{4\pi} .\frac{2\pi^2 ir^2}{R}\)
∴ mutual inductance between the coils
M = \(\frac{\phi}{i} = \) \(\frac{\mu_0}{4\pi} \frac{2\pi^2 r^2}{R}\)