Correct option is : (4) \(5 \mathrm{~m}\)
K.E. just before striking the ground \(K_{1}=m g h_{1}=m g(10)\)
K.E. just after striking the ground \(=K_{1}-\frac{50}{100} K_{1}=\frac{50}{100} K_{1}=\frac{K_{1}}{2}=K_{2} \)
\(\text { Now, } K_{2}=m g h_{2} \)
\(\Rightarrow \frac{K_{1}}{2}=m g h_{2} \)
\( \Rightarrow \frac{m g(10)}{2}=m g h_{2} \Rightarrow h_{2}=5 \mathrm{~m} \)