Correct option is (1) \(\frac{I_0}{16}\)
\(I_1 = \frac{I_0}2\)
\(I_B = (I_1) \cos^2 60^\circ\)
\(= \frac{I_0}2 (\frac 12)^2 \)
\(= \frac{I_0}8\)
\(I_C = I_B \cos^2 45^\circ\)
\(= \frac{I_0} 8 \times \left(\frac 1{\sqrt 2}\right)^2\)
\(= \frac{I_0}{16}\)