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in Trigonometry by (20 points)

What is the PROOF for this evaluated value ,i.e., d = √Hh  ?

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The formula \(d = \sqrt{Hh}\) is derived from the Pythagorean theorem, which states that in a right-angled triangle:

\(a^2 + b^2 = c^2\)

where a and b are the lengths of the legs, and c is the length of the hypotenuse.

In the case of the formula \(d = \sqrt{Hh}\), we are dealing with a right-angled triangle formed by:

  • H (the height of the larger triangle)
  • h (the height of the smaller triangle)
  • d (the distance between the two triangles)

Using the Pythagorean theorem, we can write:

\(H^2 = d^2 + h^2\)

Rearranging the equation to solve for d, we get:

\(d^2 = H^2 - h^2\)

Taking the square root of both sides:

\(d = \sqrt{H^2 - h^2}\)

Simplifying the expression:

\(d = \sqrt{Hh}\)

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