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in Physics by (60.1k points)

\(\frac{1}{4 \pi \epsilon_{0}}\) का मान होता है-

(A) \(9 \times 10^{9} \mathrm{Nm}^{2} \mathrm{c}^{-2}\)

(B) \(9 \times 10^{-9} \mathrm{Nm}^{2} \mathrm{c}^{-2}\)

(C) \(9 \times 10^{12} \mathrm{Nm}^{2} \mathrm{c}^{-2}\)

(D) \(9 \times 10^{-12} \mathrm{Nm}^{2} \mathrm{c}^{-2}\)

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1 Answer

+1 vote
by (59.3k points)

सही विकल्प है (A) \(9 \times 10^{9} \mathrm{Nm}^{2} \mathrm{c}^{-2}\)

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