Question

Oxidation number of S in H₂S₂O₇ is

(a) + 4

(b) -6

(c) -5

(d) +6

Answer 1

Correct option is (d) +6

Let, the oxidation state of sulphur in H₂S₂O₇ be x.

∴ 2(+1) + 2(x) + 7(-2) = 0

2 + 2x - 14 = 0

2x = 12

x = \(\frac{12}2\)

x = +6