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i) For \( \vec{v}_{1}=2 \hat{i}-3 \hat{j} \) and \( \overrightarrow{ v _{2}}=-6 \hat{i}+5 \hat{j} \), determine the magnitude and direction of \( \overrightarrow{v_{1}}+\overrightarrow{v_{2}} \).

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\(\vec {v_1} + \vec {v_2} = (2\hat i - 3\hat j) + (-6\hat i + 5\hat j)\)

\(= (2\hat i - 6 \hat i) + (-3 \hat j + 5 \hat j)\)

\(= - 4 \hat i + 2 \hat j\)

\(\therefore |\vec {v_1} + \vec {v_2}| = \sqrt{(-4)^2 + 2^2}\)

\(= \sqrt {20}\)

\(= \sqrt {4 \times 5}\)

\(= 2 \sqrt 5\)

Comparing \(\vec {v_1} + \vec {v_2} \) with \(\vec R =R _x \hat i +R _y \hat j \)

\(\Rightarrow\) \( R_{x} = - 4\) and \(R_{y} = 2\)

Taking to be angle made by \(\vec R\) with X-axis,

\(\therefore \theta = \tan^{-1} \left(\frac{R_y}{R_x}\right)\)

\(= \tan^{-1} \left( \frac 2 {-4}\right)\)

\(= \tan^{-1} \left( \frac 1{-2}\right)\) with X-axis

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