Question

If 10 gm of a gas at atmospheric pressure is cooled from 273°C to 0°C keeping the volume constant, its pressure would become

(a) 1/2 atm

(b) 1/273 atm

(c) 2 atm

(d) 273 atm

Answer 1

Correct option is (a) 1/2 atm

Given,

T₁ = 273° or 546.15 K

P₁ = 1 atm

T₂ = 0°C or 273.15 K

P₂ = ?

\(\therefore \frac{P_1}{T_1} = \frac{P_2}{T_2}\)

\(\therefore P_2 = \frac{P_1 \times T_2}{T_1}\)

\(= \frac{1 \times 273.15}{546.15}\)

\(= \frac 12 atm \) or \(5.05 \times 10^4 Nm^{-2}\)