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The V.D. of a gas is 11.2. The volume occupied by 11.2 gm of this gas at N.T.P. is

(a) 22.4 litres

(b) 11.2 litres

(c) 1 litre

(d) 2.24 litres

1 Answer

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Correct option is (b) 11.2 litres

Mol. mass = 2 x V.D. = 2 x 11.2 = 22.4 g

Volume of 11.2 g of the gas at STP = \(\frac{22.4 \times 11.2}{22.4} = 11.2\ l\)

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