C6H6 (Benzene)
- Molar mass of C6H6 = (6 × 12.01) + (6 × 1.008) = 72.06 + 6.048 = 78.108 g/mol
- Mass of carbon in C6H6 = 6 × 12.01 = 72.06 g
- Percentage of carbon = (72.06 / 78.108) × 100 ≈ 92.3%
C2H6 (Ethane)
- Molar mass of C2H6 = (2 × 12.01) + (6 × 1.008) = 24.02 + 6.048 = 30.068 g/mol
- Mass of carbon in C2H6 = 2 × 12.01 = 24.02 g
- Percentage of carbon = (24.02 / 30.068) × 100 ≈ 79.3%
C2H4 (Ethene)
- Molar mass of C2H4 = (2 × 12.01) + (4 × 1.008) = 24.02 + 4.032 = 28.052 g/mol
- Mass of carbon in C2H4 = 2 × 12.01 = 24.02 g
- Percentage of carbon = (24.02 / 28.052) × 100 ≈ 85.5%
C3H4 (Propyne)
- Molar mass of C3H4 = (3 × 12.01) + (4 × 1.008) = 36.03 + 4.032 = 40.062 g/mol
- Mass of carbon in C3H4 = 3 × 12.01 = 36.03 g
- Percentage of carbon = (36.03 / 40.062) × 100 ≈ 89.8%
Comparing the percentages:
- C6H6: ~92.3%
- C2H6: ~79.3%
- C2H4: ~85.5%
- C3H4: ~89.8%
The molecule with the maximum percentage of carbon by mass is C6H6 (Benzene), with approximately 92.3% carbon.