Question

Two tuning forks when sounded together produce 4 beats per second. The frequency of one tuning fork is 256 Hz. When some wax is loaded on the arm of the second tuning fork, then 6 beats per second are produced. Find out the frequency of the second tuning fork.

Answer 1

v₁ = 256 Hz; b = 4 beat/second

On loading wax on arm of the second tuning fork
v₂ = ?

we consider v₂ = 200 Hz, then after loading with wax, its frequency will be little less than 260 Hz. So with the first tuning fork the beat frequency will decrease, which is according to the question.

∴ v₂ ≠ 260 Hz

∴ v₂ = 252 Hz