Question

 A parallel-plate capacitor is connected to a cell. Its positive plate A and its negative palte B have charges +Q and –Q respectively. A third plate C, identical to A and B, with charge+Q, is now introduced midway between A and B, parallel to them, which of the following are correct?

(A) The charge on the inner face of B is now -3Q/2

(B) There is no change in the potential difference between A and B. 

(C) The potential difference between A and C is onethird of the potential difference between B and C. 

(D) The charge on the inner face of A is now Q/2.

Answer 1

Correct option (A, B, C, D) 

Explanation: 

Now the charge on outer surfaces should be same