Correct option is: (2) \(\frac{68}{157}\)
\(\frac{1}{2 + \cfrac{1}{3+ \cfrac{1}{4 + \frac{1}{5}}}}\)
\(= \frac{1}{2 + \cfrac{1}{3 + \frac{1}{\frac{21}{5}}}}\)
\(= \frac{1}{2+ \cfrac{1}{3 + \frac{5}{21}}}\)
\(= \frac{1}{2 + \frac{1}{\frac{68}{21}}}\)
\(= \frac{1}{2 + \frac{21}{68}}\)
\(= \frac{1}{\frac{157}{68}}\)
\(= \frac{68}{157}\)