Question

Self-Inductance of a coil is 5 mH. If 2A of current flow through this coil then magnetic flux linked with coil will be

(A) 1 wb

(B) 0.1 wb

(C) 0.01 wb

(D) 0.00 wb

Answer 1

Correct option is (C) 0.01 wb

emf = \(L \frac {dI}{dt} = \frac {d\phi}{dt}\)

\(\Rightarrow LdI = d\phi\)

Integrating both side we will get,

\(L \int d I = \int d \phi\)

\(\Rightarrow 5 \times 10^{-3} \times 2 = \phi\)

\(\Rightarrow \phi = 0.01 \ wb\)

Answer 2

Correct option is: (C) 0.01 wb