Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
59 views
in Mathematics by (54.3k points)
closed by

In a right angled triangle, if perpendicular, base and hypotenuse are p, b and h respectively then h =

(A) \(\sqrt{p^{2}-b^{2}}\)

(B) \(\sqrt{b^{2}-p^{2}}\)

(C) \(\sqrt{p^{2}+b^{2}}\)

(D) \(\sqrt{(p+b)^{2}}\)

1 Answer

+1 vote
by (50.3k points)
selected by
 
Best answer

Correct option is (C) \(\sqrt{p^{2}+b^{2}}\)   

In a right-angled triangle, the relationship between the perpendicular (p), the base (b), and the hypotenuse (h) is given by the Pythagorean theorem.

\(h^2 = p^2+b^2\)   

\(\therefore \ h =\sqrt{p^2+b^2}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...