Question

A bullet of kinetic energy of 125 J strikes a lead block where temperature rises by 50°C. If specific heat of lead is 0.1 J/g-°C then mass of lead block is (Assume half of kinetic energy of bullet is converted to heat) m gram then 2m is

Answer 1

 Answer is : 25

\(Q = ms\Delta T \Rightarrow\frac{125}{2} = m\times 0.1\times 50\)

\(m = \frac{125}{10} = 12.5\ gm\)