Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
241 views
in Mathematics by (50.3k points)

If the equation \(a(b-c) x^2+b(c-a) x+c(a-b)=0\) has equal roots and if a + c = 5 and \(b=\frac{16}{5},\) then the value of \(a^2+c^2\) is equal to

Please log in or register to answer this question.

1 Answer

+1 vote
by (54.3k points)

Answer is "9" 

Clearly 1 satisfy \(\Rightarrow\) other root is also 1 . 

\(\Rightarrow \frac{c(a-b)}{a(b-c)}=1\) (using product of roots)  

\(\Rightarrow c(a-b) = a(b-c)\)  

equation

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...