Question

A bag contains 6 white balls and 4 black balls, two balls are drawn at random, then the probability that both balls are white is

(1) \(\frac{1}{4}\)  

(2) \(\frac{2}{3}\)  

(3) \(\frac{1}{3}\)    

(4) \(\frac{1}{2}\)

Answer 1

Correct option is (3) \(\frac{1}{3}\)

P(ww) = \(\frac{6}{10} \times \frac{5}{9} = \frac{1}{3}\)