Question

In a YDSE, the distance of the 10^th bright fringe from the central maxima is 10 mm when light of wavelength used is 600 nm. Find the distance (in mm) of the 10^th bright fringe from the central maxima if light of wavelength 660 nm is used instead.

Answer 1

Answer is : 11 

\(y = 10\frac{\lambda D}{d}\)

\(\frac{y_2}{y_1} = \frac{\lambda _2}{\lambda _1}\)

\(y^2 = \frac{\lambda _2}{\lambda _1}\times y_1\)

\(\frac{660\ nm}{600\ nm}\times 10\ mm\)

= 11 mm