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Consider the following reaction

\(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}}[\mathrm{A}] \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{2} \mathrm{SO}_{4}}[\mathrm{~B}]+\mathrm{K}_{2} \mathrm{SO}_{4}\)

The products \([\mathrm{A}]\) and \([\mathrm{B}]\), respectively are :

(1) \( \mathrm{K}_{2} \mathrm{Cr}(\mathrm{OH})_{6}\) and \(\mathrm{Cr}_{2} \mathrm{O}_{3}\)

(2) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and \(\mathrm{Cr}_{2} \mathrm{O}_{3}\)

(3) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

(4) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and CrO

1 Answer

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Best answer

Correct option is : (3) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

\(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}} \underset{[\mathrm{A}]}{\mathrm{K}_{2} \mathrm{CrO}_{4}} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{5} \mathrm{O}_{4}} \underset{[\mathrm{~B}]}{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}+\mathrm{K}_{2} \mathrm{SO}_{4}\)

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