Consider the following reaction
\(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}}[\mathrm{A}] \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{2} \mathrm{SO}_{4}}[\mathrm{~B}]+\mathrm{K}_{2} \mathrm{SO}_{4}\)
The products \([\mathrm{A}]\) and \([\mathrm{B}]\), respectively are :
(1) \( \mathrm{K}_{2} \mathrm{Cr}(\mathrm{OH})_{6}\) and \(\mathrm{Cr}_{2} \mathrm{O}_{3}\)
(2) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and \(\mathrm{Cr}_{2} \mathrm{O}_{3}\)
(3) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)
(4) \(\mathrm{K}_{2} \mathrm{CrO}_{4}\) and CrO