Correct option is: (C) -4
For a quadratic equation \(a x^2+b x+c,\)
Product of zeros \((\alpha \beta) = \frac{c}{a}\)
In quadratic polynomial \(x^2+3 x-4,\) we have:
a = 1
b = 3
c = -4
So,
Product of zeros \((\alpha \beta) =\frac{c}{a} \)
\(=-\frac{4}{1} \)
= -4