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in Mathematics by (45.5k points)
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एक पाँसा फेंकने पर, 3 से बड़ी भाज्य संख्या के प्राप्त होने की प्रायिकता है :

(A) \(\frac{1}{6}\)

(B) \(\frac{1}{3}\)

(C) \(\frac{1}{2}\)

(D) \(\frac{2}{3}\)

2 Answers

+1 vote
by (55.9k points)
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Best answer

सही विकल्प है: (B) \(\frac{1}{3}\)   

Total numbers of outcomes while throwing dice is 1, 2, 3, 4, 5, 6 

Number greater than 3 are: 4, 6 out of which only one number appears while throwing dice.

\(\therefore \) Probability (number greater than 3) = \(\frac{\text{favorable outcome}}{\text{Total number of outcomes}}\)  

\(=\frac{2}{6}\) 

\(=\frac{1}{3}\)

+1 vote
by (45.6k points)

सही विकल्प है: (B) \(\frac{1}{3}\)

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