सही विकल्प है: (B) \(\frac{1}{3}\)
Total numbers of outcomes while throwing dice is 1, 2, 3, 4, 5, 6
Number greater than 3 are: 4, 6 out of which only one number appears while throwing dice.
\(\therefore \) Probability (number greater than 3) = \(\frac{\text{favorable outcome}}{\text{Total number of outcomes}}\)
\(=\frac{2}{6}\)
\(=\frac{1}{3}\)