Question

The number of unpaired electrons and hybridisation of [Mn(CN)6]^3– , respectively are :-

(1) 4 and d²sp³

(2) 4 and sp³d²

(3) 2 and d²sp³

(4) 2 and sp³d²

Answer 1

Correct option is : (3) 2 and d²sp³

[Mn(CN)6]^3– \(\Rightarrow\) Mn in +3 oxidation state

  ^{\(\text{pairing will take place.}\)}

CN^– ion in presence of Mn³⁺ ion, acts as strong field ligand.

Total 2 unpaired e^– are present in [Mn(CN)₆]^3–

. Its hybridisation will be d²sp³ .