Question

In lead storage battery during charging oxidation state of lead show changes

at anode from x₁ to y₁

at cathode from x₂ to y₂

Find value of x₁, y₁, x₂, y₂

(1)  \(\text{x}_1 = +2, \ \text{y}_1 = 0 \\ \text{x}_2 = +2, \ \text{y}_2 = +4\)

(2)  \(\text{x}_1 = +4, \ \text{y}_1 = 0 \\ \text{x}_2 = +2, \ \text{y}_2 = +4\)

(3) \(\text{x}_1 = 0, \ \text{y}_1 = +2 \\ \text{x}_2 = +4, \ \text{y}_2 = +2\)

(4) \(\text{x}_1 = +2, \ \text{y}_1 = 0 \\ \text{x}_2 = +4, \ \text{y}_2 = 0\)

Answer 1

Correct option is : (1) \(\text{x}_1 = +2, \ \text{y}_1 = 0 \\ \text{x}_2 = +2, \ \text{y}_2 = +4\)

On changing the lead storage battery PbSO₄(s) at anode is converted into Pb and PbSO₄(s) at cathode is converted into PbO₂.