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Find the dimensions of the physical quantity \(\frac{2B^2\mu_0}{\varepsilon _0}\).

(Symbols have their usual meanings)

(1) \(M^4L^{-2} T^{-4} A^{-1}\)

(2) \(M^4 L^4 T^{-10}A^{-6}\)

(3) \(M^{-1} L^{-2} T^{-3} A^{-1}\)

(4) \(M^{-1} L^{-4}A^{-1}\)

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1 Answer

+1 vote
by (18.7k points)

Correct option is : (2) \(M^4 L^4 T^{-10}A^{-6}\)

\([B] = MT^{-2} A^{-1}\)

\([\mu_0] = MLT^{-2}A^{-2}\)

\([\varepsilon _0] = M^{-1}L^{-3}T^4 A^2\)

\([\frac{2B^2\mu_0}{\varepsilon _0}] = M^4 L^4 T^{-10} A^{-6}\)

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