Answer is : 4 m
\(\frac{n_2}{v} - \frac{n_1}{u} = \frac{n_2 - n_1}{R}\)
\(\frac{3}{2\times 200} - \frac{1}{-x} = \frac{\frac{3}{2}-1}{+50}\)
\(\frac{3}{400}+ \frac{1}{x} = \frac{1}{100}\)
\(\frac{1}{x} = \frac{4}{400} - \frac{3}{400} = \frac{1}{400}\)
\(x = 400\ cm = 4\ m\)