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Find the dimension of \(\frac{\phi _E}{\phi _B} = c\) where, \(\phi _E\) represents electric flux and \(\phi _B \) represents magnetic flux. Then dimension of c is given by \(M^aL^bC^c:-\)

(1) a = 1, b = 1, c = –1

(2) a = 0, b = 1, c = –1

(3) a = 1, b = 2, c = –1

(4) a = 1, b = 2, c = 2

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1 Answer

+1 vote
by (45.5k points)

Correct option is : (2) a = 0, b = 1, c = –1

\(\left(\frac{\phi_E}{\phi _B}\right) = \left[\frac{EA}{BA}\right] = LT^{-1}\)

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