Question

Electronic configuration of four elements A, B, C and D are given below:

(A) \(1s^22s^22p^3\)

(B) \(1s^22s^22p^4\)

(C) \(1s^2 2s^2 2p^5\)

(D) \(1s^2 2s^2 2p^2\)

Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

(1) A < D < B < C

(2) A < C < B < D

(3) A < B < C < D

(4) D < A < B < C

Answer 1

Correct option is: (4) D < A < B < C

(A) \(1s^2 2s^2 2p^3 \Rightarrow N\)

(B) \(1s^2 2s^2 2p^4 \Rightarrow O\)

(C) \(1s^2 2s^2 2p^5 \Rightarrow F\)

(D) \(1s^2 2s^2 2p^2 \Rightarrow C\)

Order of electronegativity

F > O > N > C

C > B > A > D