The distance of the origin (0, 0, 0) from the plane –2x + 6y – 3z = –7 is (a) 1 unit (b) √2 units ​

Question

The distance of the origin (0, 0, 0) from the plane –2x + 6y – 3z = –7 is

(a) 1 unit

(b) \(\sqrt 2\) units

(c) \(2\sqrt 2\) units

(d) 3 units

Answer 1

Correct option is : (a) 1 unit

By formula of distance of point from plane

distance \(= |\frac{-2(0)+6(0)-3(0)+7}{\sqrt{4+36+9}}| = |\frac{7}{7}|= 1\) unit