Question

Molybdenum has a density of 10.2 × 10³ kg/m³ with atomic weight 95.94 g/mol. Calculate its atomic radius.

(a) 1.36 Å (b) 13.6 Å (c) 0.136 Å (d) 2.42 Å  

Answer 1

Correct option (a) 1.36 Å

Explanation:

where, a = sides of unit cell

N_A = Avogadro` s number = 6.023 × 10²³

n = number of atomsinunitcell

A = atomic weight

Molybdenum has BCC structure

∴ n = 2 and a = 4r/√3

∴  r = 1.36 Å