Re–write the given set of simultaneous equations as
(D2 + 3)x – 2y = 0 …(1)
(D2 – 3)x + (D2 + 5)y = 0 …(2)
In order to make above equations separately in x(t) and y(t) i.e. to eliminate x, first operate these equations by (D2 – 3) and (D2 + 3) respectively and then subtract (1) from (2), we get
[(D2 + 3)(D2 + 5) + 2(D2 – 3)]y = 0
On simplification,
(D4 + 10D2 + 9)y = 0 … (3)
Corresponding auxiliary equation becomes
D4 + 10D2 + 9 = 0 or (D2 + 1)(D2 + 9) = 0 i.e. D = ± i, ± 3i
Thus, y(C.F.) = (a1cos t + a2sint) + (a3cos3t + a4sin3t) … (4)
To find x, eliminate y from (1) and (2). Operate (1) by (D2 + 5) and multiply (2) by 2 and then add the two,
(D4 + 10D2 + 9)x = 0 (an equation identical to (3)) i.e. D = ± i, ± 3i ...(5)
Thus, x(C.F.) = (b1cost + b2sint) + (b3cos 3t + b4sin3t) …(6)
To find the relation between constants involved in (4) and (6)
Substitute values of x and y in either of the given equations, say in (1), we get 2(b1 – a1)cost + 2(b2 – a2)sint – 2(3b3 + a3)cos3t – 2(3b4 + a4)sin3t = 0 …(7)
Which must holds for all t.
On equating co–efficient of cost, sint, cos3t, sin3t, we get