Question

A compound (80 g) on analysis gave C = 24 g, H = 4 g, O = 32 g. Its empirical formula is 

(A) C₂H₂O₂ 

(B) C₂H₂O 

 (C) CH₂O₂ 

(D) CH₂O 

Answer 1

A compound (80 g) on analysis gave C = 24 g, H = 4 g, O = 32 g. Its empirical formula is  CH₂O.

Explanation :-

C = 24 g, H = 4 g, O = 32 g 

So, Molecular formula = C₂H₄O₂ 

 So, Empirical formula = CH₂O 

 (Simplest formula).