Correct Option :- (a) 15 cm
Explanation :-
As the incident beam is parallel in absence of concave lens it will form an image at a distance v from it such that
(1/v) – (1/-∞) = (1/20) ⇒ v = 20 cm = f
Now since d is the distance between convex & concave lens. The distance of image I from concave lens will be (20-d). Since the image I will act as an object for concave lens
which forms its image at ∞, so
(1/v)- (1/u) = (1/f) (1/∞) – [1/(20-d)] = 1/(-5) ,
20-d =5 ⇒ d = 15 cm