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0 votes
45.8k views
in Mathematics by (215 points)
edited by

If a=(2^2*3^3*5^4)and b=(2^3*3^2*5),then find HCF(a,b)

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2 Answers

+2 votes
by (14.7k points)

It is given that: 

a = (22 × 33 × 54 ) and b = (23 × 32 × 5) 

∴HCF (a,b) = Product of smallest power of each common prime factor in the numbers. 

 = 22 × 32 × 5 

 = 180

by (215 points)
Thankyousomuch
0 votes
by (20 points)

Step-by-step explanation:

The given numbers are

a= 2^2\times 3^3\times 5^4

b=2^3\times 3^2\times 5

Highest Common Factor of a and b :

It is a largest positive integer that divides both a and b.

H.C.F. = 2^2 \times 3^2 \times 5

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