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20 J work is required to stretch a spring through 0.1 m. Find the force constant of the spring. If the spring is further stretched through 0.1 m. Calculate work done.

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P.E. of spring when stretched through a distance 0·1 m,

U = W.D. = 1/2 Kx2 = 20 J

or K = 4000 N/m 

when spring is further stretched through 0·1 m, then P.E. will be :

U' = 1/2k(0.2)2 = 80 J

∴ W.D. = U′ – U = 80 – 20 = 60 J.

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