Suppose we have loga (b), we want to change it on exponential (e) base, then it can be written as:
loga(b)=loga(e)⋅loge(b)
Let's say we have, y = c ⋅ f ( x ) , where c is a constant then, y ' = c ⋅ f ' ( x )
Now, this is quite straightforward to differentiate, as log10(e) is constant, so only remaining function is loge(x)
Hence,
y' = log10(e) . 1/x