Question

A metal piece of 50 g specific heat 0.6 cal/gºC initially at 120ºC is dropped in 1.6 kg of water at 25ºC. Find the final temperature or mixture.

Answer 1

m₁c₁ (θ₁ – θ) = m₂c₂ (θ – θ₂) 

∴ c₂ = 1 cal/gmºC 

∴ 50 × 0.6 × (120 – θ) 

= 1.6 × 10³ × 1 × (θ – 25) 

θ = 26.8ºC