Correct option (c) CoSO4
Explanation:
In (NH4)2 [(TiCl6)], Ti4+ (3d0 4s0 ) has no unpaired electrons.
In K2Cr2O7 , Cr6+ (3p6 d0 ) has no unpaired electrons. In CoSO4 , Co2+ (d7 ) has unpaired electrons in d-orbitals, so it is both paramagnetic and coloured.
In K3 [Cu(CN)4], Cu+ (3d10), has no unpaired electron.